The internal energy of monoatomic ideal gas is 1.5 nRT. One mole of helium is kept in cylinder of cross section `8.5cm^2`. The cylinder is closed by a light frictionless piston. The gas is heated slowly in a process during which a total of 42 J heat is given to the gas. If the temperature rises through `2^@C` find the distance moved by the piston. Atmospheric pressure`=100kPa`

The internal energy of monoatomic ideal gas is 1.5 nRT. One mole of he

1.	The internal energy of monoatomic ideal gas is 1.5 nRT. One mole of helium is kept in cylinder of cross section `8.5cm^2`. The cylinder is closed by a light frictionless piston. The gas is heated slowly in a process during which a total of 42 J heat is given to the gas. If the temperature rises through `2^@C` find the distance moved by the piston. Atmospheric pressure`=100kPa`
Answer» given `n=1`,`A=85xx10^-4m^2`,`DeltaQ=42J`,` DeltaT=2^@C` Atmospheric pressure `P_0=100Pa=10^5(N)/(m^2)`,`U=1.5nRT` The gas is heated slowly i.e., pressure remains constant `DeltaW=DeltaQ-DeltaU=42-1.5xx1xx8.3xx2=17.1J` `P_0DeltaV=P_0Ax=DeltaW` `10^5xx8.5xx10^-4x=17.1` `x=0.2m=20m` x distance moved by piston.

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