1.

The internal energy of one mole of nitrogen at 300 K is 6235 J. What is the internal energy of one mole of nitrogen at 400 K ?

Answer»

u1\(\frac52\)RT1 and u2\(\frac52\)RT2

\(\therefore\) u2 = u\((\frac{T_2}{T_1})\) = (6235) \((\frac{400}{300})\) = 8313 J

This is the required quantity.



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