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The internal energy of one mole of nitrogen at 300 K is 6235 J. What is the internal energy of one mole of nitrogen at 400 K ? |
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Answer» u1 = \(\frac52\)RT1 and u2 = \(\frac52\)RT2 \(\therefore\) u2 = u1 \((\frac{T_2}{T_1})\) = (6235) \((\frac{400}{300})\) = 8313 J This is the required quantity. |
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