1.

The internal measure of cuboidal room are 12m× 8m×4m×.find the total cost of whitewashing all four walls of a room, if the cost of white washing is rs5per m^2 .what will be the cost of white washing if the ceiling of the room is also whitewashed.​

Answer»

ANSWER :

\bold{Cost\:of\:whitewashing\:4\:walls = Rs.800}

\bold{Total\: Cost = Rs. 1280 }

Step-by-step EXPLANATION:

\bf\red{Given:-}\begin{cases}\sf\red{Length = 12\:m}\\\sf\green{Breadth=8\:m}\\\sf\orange{Height = 4\:m}\\\sf\green{Rate = Rs.5 \: per\:{m}^{2} }\end{cases}

\bf\red{To\:find:-}\begin{cases}\sf\green{Cost\:of\:whitewashing\;4\:walls=?}\\\sf\purple{Cost\:of\:whitewashing\:including\:ceiling=?}\end{cases}

\rule{300}{1}

\bigstar\sf\red{ We\:know\:that:-}

{\boxed{\sf\green{Area\:of\:4\:walls = 2(l + b)\times h}}}

\longrightarrow\sf\green{Area\:of\:4\:walls = 2(12 + 8)\times 4 }\\\\\longrightarrow\sf\red{Area\:of\:4\:walls = 2 \times 20 \times 4} \\\\\longrightarrow\sf\purple{Area\:of\:4\:walls = 160\:{m}^{2} }

\bigstar\sf\green{\ Cost\:of\:whitewashing = Area \times Rate } \\\\\longrightarrow\sf\red{Cost\:of\:whitewashing =Rs. (160 \times 5) } \\\\\longrightarrow\underline{\boxed{\bold{Cost\:of\:whitewashing = Rs.800}}}

\rule{100}{2}

\sf\red{We\:know\:that,}

\bigstar \ \underline{\boxed{\bold{Area\:of\:ceiling = l \times b}}}

\longrightarrow\sf\green{Area\:of\:ceiling = 12 \times 8 }\\\\\longrightarrow\sf\orange{Area\:of\:ceiling = 96\:{m}^{2}}

\bigstar\bold{\ Cost = Area \times Rate} \\\\\longrightarrow\sf\red{Cost = Rs.(96\times 5) } \\\\\longrightarrow\underline{\boxed{\bold{Cost = Rs.480 }}}

\rule{100}{2}

\bigstar\sf{\ Total\:cost = Rs.(800 + 480)} \\\\\longrightarrow\underline{\boxed{\bold{Total\:cost = Rs.1280}}}



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