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The internal resistance of a `2.1 V` cell which gives a current `0.2 A` through a resistance of `10 Omega`A. `0.2 Omega`B. `0.5 Omega`C. `0.8Omega`D. `1.0Omega` |
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Answer» Correct Answer - B `I=(E)/(R+r)` `0.2=(2.1)/(10+r)` `2+0.2r=2.1` `0.2r=2.1` `r=0.5Omega` |
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