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The internal resistance of a `2.1 V` cell which gives a current `0.2 A` through a resistance of `10 Omega`A. `0.2 Omega`B. `0.5 Omega`C. `0.8Omega`D. `1.0Omega`

Answer» Correct Answer - B
`I=(E)/(R+r)`
`0.2=(2.1)/(10+r)`
`2+0.2r=2.1`
`0.2r=2.1`
`r=0.5Omega`


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