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The internal resistance of two diodes usded in fulllwave rectifier is 20 omega(i) the maximumand mena load current(ii) rmsvalueof load current |
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Answer» SOLUTION :`V_(max)= 50 V` (i) Maximumloadcurrent `(ii)I_(max)= (I_(C ))/( SQRT(2))= (0.07)/(1.414)` `=0.05A` |
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