1.

The internal resistance of two diodes usded in fulllwave rectifier is 20 omega(i) the maximumand mena load current(ii) rmsvalueof load current

Answer»

SOLUTION :`V_(max)= 50 V`
(i) Maximumloadcurrent
`(ii)I_(max)= (I_(C ))/( SQRT(2))= (0.07)/(1.414)`
`=0.05A`


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