1.

The inversion of cane sugar proceeds with half life of 500 minute at pH=5 for any concentration of sugar. However if pH=6 the half life changes to 50 minutes. The rate law expression for sugar inversioncan be written as

Answer»

`r=K["sugar"]^(2)[H^(+)]^(0)`
`r=k["sugar"]^(1)[H^(+)]^(0)`
`r=k["sugar"]^(1)[H^(+)]^(1)`
`r=K["sugar"]^(0)[H^(+)]^(1)`

SOLUTION :`5""500,((t_(1//2))_(1))/((t_(1//2))_(2))=[([H^(+)]_(2))/([H^(+)]_(1))]^(n-1),(10)^(1)=(10^(-1))^(n-1),(10)^(1)=(10)^((-n+1)),n=0`
`6""50`


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