1.

The inversion of sucrose (C_(12)H_(22)O_(11)) is a first order reaction and is studied by measuring angle of rotation at different time intervals. C_(12)H_(22)O_(11) + H_(2)O overset(H^(+)) to underset("glucose")(C_(6)H_(12)O_(6)) + underset("fructose")(C_(6)H_(12)O_(6)). if (r_(infty)-r_(0)) and (r_(infty)-r_(t))(a-x), then 50% invertion will be completed when:

Answer»

`r_(0) = 2r_(t)-r_(infty)`
`r_(0) = r_(t) - r_(infty)`
`r_(0) = r_(t) - 2r_(infty)`
`r_(0) = r_(t) + r_(infty)`

SOLUTION :`k=(2.303)/t log (r_(infty)-r_(0))/((r_(infty)-r_(t))`…………..(i)
`(2.303/t) log (a/(a//2))` …………..(ii)
`=(2.303)/t LOG2` ………….(iii)


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