1.

The ionic product of water at 25^(@)C is 10^(-4). The ionic product at 90^(@)C will be

Answer»

`1 xx 10^(-20)`
`1 xx 10^(-12)`
`1 xx 10^(-14)`
`1 xx 10^(-16)`

Solution :When INCREASING the temperature the value of ionic product also INCREASES.


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