1.

The ionisation constant of ammonium hydroxide is 1.77xx10^(-5) at 298 K. Hydrolysis constant of ammonium chloride is :

Answer»

`6.5xx10^(-12)`
`5.65xx10^(-13)`
`5.65xx10^(-12)`
`5.65xx10^(-10)`

SOLUTION :`K_(h)=(K_(w))/(K_(B))=(10^(-14))/(1.77xx10^(-5))=5.6xx10^(-10)`


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