1.

The ionisation energy of an electron in the ground state of helium atom is 24.6V. The energy required to remove both the electron is :

Answer»

51.8eV
79eV
38.2eV
49.2eV

Solution :Ionisation energy in GROUND state =24.6eV
Energy REQUIRED to remove 2 electrons from `He^(2+)`
`=Z^(2) (13.6)EV =(2)^(2) (13.6) =54.4eV`
So, TOTAL energy required =24.6+54.4=79eV


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