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The ionisation energy of hydrogen atom is 13.6 eV, the ionisation energy of a singly ionised helium atom would be ...... |
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Answer» Solution :Ionisation energy `EpropZ^(2)` `:.(E_(He))/(E_(H))=(Z_(He)^(2))/(Z_(H^(2)))` `=((2)^(2))/((1)^(2))` `(E_(He))/(13.6)=4` `:.E_(He)=4xx13.6=54.4eV` |
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