1.

The ionisation energy of hydrogen atom is 13.6 eV, the ionisation energy of a singly ionsed helium atom would be

Answer»

`13.6` EV
`27.2` eV
`6.8` eV
`54.4` eV

Solution :`E_(2)^(1) = (2)^(2) E_(1) = 4 xx 13.6 = 54.4 eV`


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