1.

The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiation of 6 wavelengths. During which of the following transitions will the maximum wavelength radiation be emitted ?

Answer»

N=3 to n=1
n=2 to n=1
n = 4 to n=3
n=3 to n = 2

Solution :`(n(n-1))/(2)=6`
`:.n^(2)-n-12=0`
`:.(n-4)(n+3)=0 or n=4`


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