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The irradiation of lithium and beryllium targets by a monoergic stram of protons reveals that the reaction `Li^(7)(p,n) 1.65 MeV` is initialted whereas the reaction `Be^(9)(p,n)B^(9)-1.85MeV` does not take place. Find the possible values of kinetic energy of the protons. |
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Answer» Since the reaction `Li^(7)(p,n)Be^(7)(Q= -1.65MeV)` is initiated, the incident proton energy must be `ge(1+(M_(p))/(M_(d)))xx1.65= 1.89MeV` since the reaction `Be^(9)(p,n)B^(9)(Q= -1.85MeV)` is not initiated `Tle(1+(M_(p))/(M_(ve)))xx1.85= 2.06MeV` Thus `1.89MeVleT_(p)le2.06MeV` |
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