1.

The isomer of an oxime is:

Answer»

`R-NO_(2)`
`R-O-C-=N`
`R-O-N-=O`
`R-CONH_(2)`

Solution :Oxime is represented by the FORMULA `R-OVERSET(H)overset(|)(C )=N-OH`
`therefore R-CONH_(2)` will will be the the isomer of oxime.


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