1.

The K_alpha and K_(beta) lines of characteristic X-ray spectrum of molybdenum are 0.76 Å and 0.64 Å respectively, The wavelength of La line is :

Answer»

1.4Å
2.4Å
4.1Å
3.6Å

Solution :`E_(2)-E_(1)=(12375)/(0.76)EV`
`E_(3)-E_(1)=(12375)/(0.64)eV`
`E_(3)-E_(2)=(12375)/(0.64)-(12375)/((0.76)`
`or lambda K_(alpha)=(12375)/(E_(3)-E_(2))=4.1Å`


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