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1. |
The `K_(alpha)` X-ray emission line of lungsten accurs at `lambda = 0.021 nm`. What is the energy difference between `K`and `L` levels in the atom? |
Answer» `Delta E = (hc)/(lambda) = (6.62 xx 10^(-34) xx 3 xx 10^(8))/(0.021 xx 10^(-9))` `= 9.46 xx 10^(-15)J = 5.9 xx 10^(4) e V = 59 ke V` |
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