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The `K.E.` of a satellite in an orbit close to the surface of the earth is `E`. Its max `K.E.` so as to escape from the gravitational field of the earth isA. `2E`B. `4E`C. `2sqrt(2)`D. `sqrt(2)E` |
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Answer» Correct Answer - A `(K_(e))/(K_(o))=(2gR)/(gR)rArr K_(e)=2K_(0)` |
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