The K.E. of photoelecttron emitted from a metal are K_(1) and K_(2) ,when it is irradiated with lights of wavelength lambda_(1) and lambda_(2) respectively .The work function of metal is …..

The K.E. of photoelecttron emitted from a metal are K_(1) and K_(2) ,w

1.	The K.E. of photoelecttron emitted from a metal are K_(1) and K_(2) ,when it is irradiated with lights of wavelength lambda_(1) and lambda_(2) respectively .The work function of metal is …..
Answer» `(K_(1)lambda_(1)-K_(2)lambda_(2))/(lambda_(2)-lambda_(1))` `(K_(1)lambda_(2)-K_(2)lambda_(1))/(lambda_(2)-lambda_(1))` `(K_(1)lambda_(1)+K_(2)lambda_(2))/(lambda_(2)+lambda_(1))` `(K_(1)lambda_(2)+K_(2)+lambda_(1))/(lambda_(2)+lambda_(1))` Solution :`(HC)/(lambda)-phi=K` `THEREFORE hc=philambda_(1)+K_(1)lambda_(1)` and `hc=philambda_(2)+K_(2)lambda_(2)` `therefore philambda_(1)+K_(1)lambda_(1)=philambda_(2)+K_(2)lambda_(2)` `therefore phi=(K_(1)lambda_(1)-K_(2)lambda_(2))/(lambda_(2)-lambda_(1))`

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The K.E. of photoelecttron emitted from a metal are K_(1) and K_(2) ,when it is irradiated with lights of wavelength lambda_(1) and lambda_(2) respectively .The work function of metal is …..

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