1.

The K.E of the electron is E when the incident wavelength is lamda. To increase the K.E of the electron to 2E, the incident wavelength must be

Answer»

`2lamda`
`(LAMDA)/(2)`
`(hclamda)/(Elamda+hc)`
`(2hclamda)/(Elamda+hc)`

ANSWER :C


Discussion

No Comment Found

Related InterviewSolutions