1.

The K_(infty) X-ray emission line of tungsten occurs at lambda = 0.021 nm.The energy difference between K and L levels in this atom is about

Answer»

`0.51`MeV
`1.2` MeV
`59` keV
136 eV

Solution :`E = (HC)/(LAMBDA) = (6.6 xx 10^(-34)xx 3 xx 10^(8))/(0.021 xx 10^(-9)) eV = 589.3 xx 10^(2) eV APPROX 59 KeV`


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