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The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal when its displacement is : (amplitude = a) : |
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Answer» `(a)/(2)` `(1)/(2)momega^(2)(r^(2)-y^(2))=(1)/(2)m omega^(2)y^(2)`. `implies""y=( r )/(sqrt(2))=(a)/(sqrt(2))`. So correct CHOICE is (B). |
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