InterviewSolution
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InterviewSolution
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The kinetic energy of a projectile at its highest position is `K`. If the range of the projectile is four times the height of the projectile, then the initial kinetic energy of the projectile is .A. `sqrt2K`B. `2 K`C. `4 K`D. `2sqrt2 K` |
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Answer» Correct Answer - B At highest point, `(1)/(2)m u_(x)^(2)=K` `:. u_(x)=sqrt((2K)/m)` `R=4 H` `(2u_(x)u_(y))/g=(4u_(y)^(2))/(2g)` `:. u_(y)=u_(x) =sqrt((2K)/m)` Now, `K_(i)1/2m u^(2) =1/2m(u_(x)^(2)+u_(y)^(2))` `=1/2m((2K)/m+(2K)/m)` `=2K`. |
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