1.

The kinetic energy of alpha-particle emitted in the alpha-decay of ""_(88)Ra^(266) is [given, mass number of Ra = 222 u]

Answer»

`5.201` Me V
`3.301` Me V
`6.023` Me V
`4.871` Me V

Solution :(d)the nuclearshouldbe `""_(88)Ra^(226) to ""_(86)Rn ^(222)+ alpha `
Energycorrespondingmass defect
`Q =[{:("(MASS NUMBEROF Ra )"),("-(Massnumberof Ru )"),("-m (4He )"):}]Uxx931.5Me V= 4.871MeV `


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