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The kinetic energy of partical moving along a circule of radius `R` depends upon the distance covered `S` and given by `K = aS` where `a` is a constant. The the force acting on the partical isA. constantB. proportional to `v`C. proportional to `v^(2)`D. inversely proportional to `v` |
Answer» Correct Answer - D ` KE prop x rArr KE =Cx rArr (1)/(2) mv^(2) =Cx` `(1)/(2) m2v(dv)/(dt) =C(dx)/(dt) rArr mv(dv)/(dt) =Cv` ` m(dv)/(dt) = rArr ma =C` `rArr F=C rarr `constant. |
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