1.

The kinetic energy of sub-atomic particle is 5.85 xx 10^(-25)J. Calculate the frequency of the particle wave. (Planck’s constant, h = 6.626 xx 10^(-34) Js)

Answer»

Solution :`K.E = 1/2 MV^2 = 5.85 xx 10^(-25) J`
By de-broglie equation ` lamda = (h)/(mv)`
`lamda = (v)/(upsilon)`
` therefroe v/v = (h)/(mv)`
or` v = (mv^2)/(h) = (2 xx 5.85 xx 10^(-25)J)/(6.626 xx 10^(-34) JS)`
` = 1.77 xx 10^9 s^(-1)`


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