1.

The kinetic energy of the electron emitted when light of frequency 3.5xx10^(15)Hz is made to strike on a metal surface havng threshold frequency 1.5xx10^(15)Hz is (h=6.6xx10^(-34)Js)

Answer»

`1.32xx10^(-18J`
`3.3xx10^(-18)J`
`6.6xx10^(-19)J`
`1.98xx10^(-19)J`

Solution :`KE=hv-hv_(0)=H(v-v_(0))`
`=6.6xx10^(-34)(3.5xx10^(15)-1.5xx10^(15))`
`=1.32xx10^(-18)J`


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