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The kinetic energy of the electron in an orbit of radius r in hydrogen atom is proportional ...... |
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Answer» `(e^(2))/(2r)` `(mv^(2))/(r)=(k(ze)(e))/(r^(2))` `:.(1)/(2)mv^(2)=(KE^(2))/(2r)[:.z=1]` Kinetic energy of electron in atom `H_(2)=(ke^(2))/(2r)` Note: There is an error in the statement of self LEARNING which is here corrected |
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