1.

The kinetic energy per kg of nitrogen molecules at 175^(@)C` is (Molecular weight of nitroegn 28 and R=3820 J/k mole K)A. `19.968xx10^(6)J`B. `1.783xx10^(5)J`C. `1.9968xx10^(5)J`D. `1.678xx10^(5)J`

Answer» Correct Answer - C
`K.E_(2)//kg=(3)/(2)(RT)/(M)=(3)/(2)xx(8320xx448)/(28)`
`=(3xx8320xx224)/(28)`
`=3xx8320xx8=24xx8320=199680`


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