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The Langmuir Hinshelwood mechanism for equimolar reactant feed is ____(a) \(\frac{aP}{(1+bP)^2}\) = -r0(b) \(\frac{P}{(1+bP)^2}\) = -r0(c) \(\frac{aP}{(bP)^2}\)= -r0(d) \(\frac{aP}{(1+bP)}\) = -r0This question was addressed to me in quiz.I want to ask this question from Packed Bed Catalytic Reactor topic in portion Packed Bed Catalytic Reactor, Fluidised Bed and Transport Reactors of Chemical Reaction Engineering

Answer»

The correct choice is (a) \(\frac{aP}{(1+bP)^2}\) = -r0

To EXPLAIN I would SAY: A + B → R

If \(\frac{A}{B}\)=1, YA = YB = 0.5 for equimolar feed

-r0 = \(\frac{kP_A P(0.5)(0.5)}{(1+(0.5k_A P)+(0.5k_B P))^2}\) = \(\frac{aP}{(1+bP)^2}. \)

Where, a and b are constants, P is the TOTAL pressure.



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