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The last member of Lymann series of Hydrogen atom is912ÅCalculate The wavelength of series limit of blamer series. |
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Answer» Solution :Rydberg formula for the wavelengths of SPECTRAL LINES in HYDROGEN spectrum is `(1)/(lamda)=R((1)/(n_(f)^(2))-(1)/(n_(i)^2))` `:.R=(1)/(913.4Å)` `:.` The short wavelength limit `lamda_(B)` for the LYMAN series would be `(1)/(lamda_(B))=R((1)/(oo^(2))-(1)/(2^(2)))=(R)/(4)` `:.lamda_(B)=(4)/(R)=4xx913.4Å` |
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