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The last term of an AP is 119 and the 8th term from the end is 91 then the common difference of the AP is |
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Answer» As PER given , we have Last term = 1198th term from the end = 91 SINCE the AP is STARTING from the end , let a = 118 and d = common difference for the given arithmetic PROGRESSION from the end.Since NTH term = a + (n-1)d119 + (8-1)d = 91 119 + 7d = 91 7d = 91 -119 7d = -28 d = -28/ = -4Now, the common difference of AP is -d = -(-4) = 4 Hence , the common difference of the AP is 4.Hope this help you |
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