The LCM of two numbers is 28 times of their HCF.The sum of their LCM a

1.	The LCM of two numbers is 28 times of their HCF.The sum of their LCM and HCF is 1740.lf one number is 240 then what is the other number?(a) 420 (b) 460 (c) 500 (d) 380
Answer» Answer: LCM = 28 \TIMES HCF i.e. L = 28 H ∴L + H = 1740 => 28H + H = 1740 => 29H = 1740 => H =174029 = 60 ∴L=28×60=1680 Now,240×secondnumber=1680×60=>Secondnumber =168060= 420 [∵Productoftwono.=LCM×HCF ] ∴Sum of digits = 4 + 2 + 0 =6 Make me brainlist

The LCM of two numbers is 28 times of their HCF.The sum of their LCM and HCF is 1740.lf one number is 240 then what is the other number?(a) 420 (b) 460 (c) 500 (d) 380

Answer»

Answer:

LCM = 28 \TIMES HCF

i.e. L = 28 H

∴L + H = 1740

=> 28H + H = 1740

=> 29H = 1740

=> H =174029 = 60

∴L=28×60=1680

Now,240×secondnumber=1680×60=>Secondnumber

=168060= 420

[∵Productoftwono.=LCM×HCF ]

∴Sum of digits = 4 + 2 + 0 =6

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