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The least count of a stop watch is 1//5 second. The time of 20 oscillations of a pendulum is measured to be 25 seconds. The minimum percentage error in the measurement of time will be : |
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Answer» `0*1%` `:.(DeltaT)/(T)XX100=(1/5)/(25)xx100=0*8%` So the correct choice is `(b)`. |
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