1.

The least count of a stop watch is 1//5 second. The time of 20 oscillations of a pendulum is measured to be 25 seconds. The minimum percentage error in the measurement of time will be :

Answer»

`0*1%`
`0*8%`
`8%`
`1.8%`

Solution :Here `T=25` SECONDS, `DeltaT=(1)/(5)`Seconds
`:.(DeltaT)/(T)XX100=(1/5)/(25)xx100=0*8%`
So the correct choice is `(b)`.


Discussion

No Comment Found

Related InterviewSolutions