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The length and breadth of a metal sheet are `1.124m and 0.002m` respectively .The area of the sheet up in four currect significant figure isA. `9.3782m^(3)`B. `9.37m^(3)`C. `9.378248 m^(3)`D. `9.378m^(3)` |
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Answer» Correct Answer - d According to rule of significant figures ●any zeros that are between non - zero also consider significant ● all none -zero digit significant. Hence , breadth of metel `b = 3.002m` has four significant figure `:.` Length of metal `= 3.124 m` has four significant figures. Since length and breadth have four significant therefore `"Area" = "length" xx "breadth"` `= 3.124 xx 3.002 = 9.378248` will also have four significant figures. Hence, `"area" = 9.378m^(2)` |
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