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The length of a metal wire is l_(1) when the tension is F_(1) and is 12 when the tension is F_(2). The original length of wire is: |
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Answer» `(l_(1)+l_(2))/2` CHANGE in length with `F_(1) = l_(1) -L` Change in length with `F_(2) = l_(2) - L` Here `Y=(F_(1))/AxxL/(l_(1)-L)=(F_(2))/AxxL/(l_(2)-L)` `F_(1)l_(2)-F_(1)L=F_(2)l_(1)-F_(2)L` `L(F_(2)-F_(1))=F_(2)l_(1)-F_(1)l_(2)` `L=(F_(2)l_(1)-F_(1)l_(2))/(F_(2)-F_(1))` Correct choice is (d). |
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