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The length of a potentiometer wire is 1m and its resistance is 4Omega. A current of 5mA is flowing in it. An unknown source of e.m.f is the source. |
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Answer» SOLUTION :`x=I rho=I=(R )/(L )=(5xx4)/(1)=20MV` `E=lx-0.40xx20=8mV` |
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