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The length of a seconds hand in watch is `1 cm.` The change in velocity of its tip in `15 s` isA. zeroB. `(pi)/(30sqrt(2)) cm//sec`C. `(pi)/(30) cm//sec`D. `(pi sqrt(2))/30 cm//sec` |
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Answer» Correct Answer - d `Deltav=2v sin ((90^(@))/2)` `=2v sin 45^(@)=2vxx1/(sqrt(2))=sqrt(2)v` `=sqrt(2)xxr omega=sqrt(2)xx1xx(2pi)/60=(sqrt(2)pi)/(30) cm//s` |
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