

InterviewSolution
Saved Bookmarks
1. |
The length of a simple pendulum is 16 cm . It is suspended by the roof of a lift which is moving upwards with an accleration of `6.2 ms^(-2)` . Find the time period of pendulum. |
Answer» Given , length of the pendulum (l) =16 cm =0.6m Acceleration of the lift (a) `=6.2 ms^(-2)` `because` Time period (T) `=2pisqrt((l)/((g+a)))=2xx3.14sqrt((0.16)/(9.8+6.2))` `=6.28 xxsqrt((0.16)/(16))` `=6.28xxsqrt((1)/(100))=(6.28)/(10)` `=0.628 s` |
|