1.

The length of a simple pendulum is 16 cm . It is suspended by the roof of a lift which is moving upwards with an accleration of `6.2 ms^(-2)` . Find the time period of pendulum.

Answer» Given , length of the pendulum (l) =16 cm =0.6m
Acceleration of the lift (a) `=6.2 ms^(-2)`
`because` Time period (T) `=2pisqrt((l)/((g+a)))=2xx3.14sqrt((0.16)/(9.8+6.2))`
`=6.28 xxsqrt((0.16)/(16))`
`=6.28xxsqrt((1)/(100))=(6.28)/(10)`
`=0.628 s`


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