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InterviewSolution
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The length of a steel wire increases by `0*5cm` , when it is loaded with a weight of `5*0kg`. Calculate force constant of the wire and workdown in stretching the wire. Take `g=10ms^(-1)`. |
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Answer» Here, `x=0*5cm=5xx10^(-3)m, F=5*0kg=50N` Force constant, `K=(F)/(x)=(50)/(5xx10^(-3)=10^(4)N//m` Work done in stretching the wire `W=(1)/(2)Kx^(2)=(1)/(2)xx10^(4)(5xx10^(-3))^(2)=(0.25)/(2)=0.125J` |
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