InterviewSolution
Saved Bookmarks
| 1. |
The length of major ofthe ellipse `(5x-10)^2 +(5y+15)^2 = 1/4(3x-4y+7)^2` isA. 10B. `20//3`C. `20//7`D. 4 |
|
Answer» `(5x-10)^(2)+(5y+15)^(2)=((3x-4y+7)^(2))/(4)` `or (x-2)^(2)+(y+3)^(2)=((1)/(2)(3x-4y+7)/(5))^(2)` `or sqrt((x-2)^(2)+(y-3)^(2))=(1)/(2)(|3x-4y+7|)/(5)` It is an ellipse , whose focus is (2,-3) directrix is 3x-4y+7=0, and eccentricity is 1/2. Length of perpendicular from the focus to the drectrix is `(|3xx2-4(-3)+7|)/(5)=5` or `(a)/(e)-ae=5` `or 2a-(a)/(2)=5` `or a=(10)/(3)` So, the length of the major of axis is 20/3 |
|