1.

The length of second pendulum is 1 m on earth. If mass and diameter of the planet is doubled than that of earth, then length becomes:

Answer»

1 m
4 m
0.5 m
2 m.

Solution :For seconds pendulum TIME period in 2 seconds
`therefore 2=2pi sqrt((L)/(m)) & 2=2pi sqrt((l.)/(m.))`
`therefore (l)/(g)=(l.)/(g.) RARR l.=l.(g.)/(g)=l.(M.)/(M)xx(R^(2))/(R.^(2))=2.(1)/(4).l`
`rArr l.=0.5l=0.5 xx 1m=0.5m`
Correct choice is (c ).


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