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The length of the perpendicular from the origin to the plane passing through the points `veca` and containing the line `vecr = vecb + lambda vecc` isA. `([vecavecbvecc])/(|vecaxxvecb+vecbxxvecc+veccxxveca|)`B. `([vecavecbvecc])/(|vecaxxvecb+vecbxxvecc|)`C. `([vecavecbvecc])/(|vecbxxvecc+veccxxveca|)`D. `([vecavecbvecc])/(|veccxxveca+vecaxxvecb|)` |
Answer» Correct Answer - c The given plane passes through `veca` and is parallel to the vectors `vecb-vecaandvecc`. So it is normal to `(vecb-veca)xxvecc`. Henec, its equation is `(vecr-veca).((vecb-veca)xxvecc)=0` or `vecr.(vecbxxvecc+veccxxveca)=[vecavecbvecc]` The length of the perpendicular from the origin to this plane is `[vecavecbvecc]/(|vecbxxvecc+veccxxveca|)` |
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