1.

The length of the potentiometer wire is 600 cm and a current of 40 mA is flowing in it. When a cell of emf 2 V and internal resistance 10Omega is balanced on this potentiometer the balance length is found to be 500 cm. The resistance of potentiometer wire will be

Answer»

`20OMEGA`
`40 Omega`
`60Omega`
`80OMEGA`

Answer :C


Discussion

No Comment Found

Related InterviewSolutions