The length of the second's pendulum is increased by 0.1%. The clock :

1.	The length of the second's pendulum is increased by 0.1%. The clock :
Answer» gains 43.2 s per DAY loses 43.2 s per day neither loses nor gains time none of the above. Solution :`T=2pi SQRT((L)/(g))` `:. (T_(2))/(T_(1))=sqrt((l_(2))/(l_(1)))=sqrt((100.1)/(100))=1.0005`. `impliesT_(2)=2(1.0005)=2.001`s Loss in time for `2" s"=2.001-2=0.001` s. `:.`Lossin time per day `=(0.001)/(2)xx24xx60xx60=43.2` s. So the CORRECT choice is (b).

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The length of the second's pendulum is increased by 0.1%. The clock :

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