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The lengths of the sides of a triangle are 5/4 cm, 7/4 cm and 3/2 cm respectively . Find its perimeter |
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Answer» Perimeter of ∆ = sum of all SIDES = (5/4 + 7/4 + 3/2) CM = (5+7+6/4) cm [ LCM is 4 ] = 18/4 cm Perimeter of ∆ = 9/2 cm Please Mark As The Brainliest...!! |
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