The level of water in a tank is 5 m high. A hole of area 1 cm^(2) is made at the bottom of the tank. The rate of leakage of water from the hole is : (g = 10 m//s^(2))

The level of water in a tank is 5 m high. A hole of area 1 cm^(2) is m

1.	The level of water in a tank is 5 m high. A hole of area 1 cm^(2) is made at the bottom of the tank. The rate of leakage of water from the hole is : (g = 10 m//s^(2))
Answer» `10^(-3)m^(3)//s` `10^(-4)m^(3)//s` `10^(-1)m^(3)//s` `10^(-2)m^(3)//s` Solution :VELOCITY with which liquid comes out of the hole `v=sqrt(2gh)` `THEREFORE` Rate of flow of WATER from the hole `="area"xx"velocity"=Axxsqrt(2gh)` `=1xx10^(-4)sqrt(2xx10xx5)=10^(-3)m^(3)s^(-1)` Thus the correct choice is (a).

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The level of water in a tank is 5 m high. A hole of area 1 cm^(2) is made at the bottom of the tank. The rate of leakage of water from the hole is : (g = 10 m//s^(2))

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