1.

The limiting molar conductances wedge^(infty) for NaCl, KBr and KCl are 126, 152 and 150 Scm^(2) mol^(–1) respectively. The wedge^(infty) for NaBr will be:

Answer»

302 S `CM^(2) MOL^(–1)`
176 S `cm^(2) mol^(–1)`
278 S `cm^(2) mol^(–1)`
`128 S cm^(2) mol^(–1)`

ANSWER :D


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