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| 1. |
The limiting molar conductances wedge^(infty) for NaCl, KBr and KCl are 126, 152 and 150 Scm^(2) mol^(–1) respectively. The wedge^(infty) for NaBr will be: |
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Answer» 302 S `CM^(2) MOL^(–1)` |
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