1.

The limiting molar conductivities (Lambda^(0)) for NaCl, KBr and KCl are 126, 152 and 150 S.cm^(2) "mol"^(-1) respectively. Then A for NaBr is

Answer»

`128 S cm^(2) MOL^(-1)`
`302 S cm^(2) mol^(-1)`
`278 S cm^(2) mol^(-1)`
`176 S cm^(2) mol^(-1)`

Answer :A


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