1.

The limiting molar conductivities of HCl, CH_(3)COONa and NaCl are respectively 425,90 and 125 mho cm^(2)mol^(-1) at 25^(@)C. The molar conductivity of 0.1 M CH_(3)COOH solution is 7.8 mho cm^(2)mol^(-1) at the same temperature. The degree of dissociation of 0.1 M acetic acid solution at the same temperature is

Answer»

0.1
0.02
0.15
0.03

Solution :`WEDGE^(@)` for `CH_(3)COOH=lamda_(CH_(3)COO^(-))^(@)+lamda_(Na^(+))^(@)`
`lamda_(H^(+))^(@)+lamda_(Cl^(-))^(@)-lamda_(Na^(+))^(@)-lamda_(Cl^(-))^(@)`
`=lamda_(CH_(3)COO^(-))^(@)+lamda_(H^(+))^(@)`
`=90+425-125=390mho" "cm^(2)mol^(-1)`
DEGREE of DISSOCIATION`(alpha)=(wedge_(m)^(@))/(wedge_(m)^(@))=(7.8)/(390)=0.02`


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